Parallel Plate Capacitor | Hindi 

Modi ji Corona discharge isi lesson Ka ek topic hai

mohit chaudhary capacitor k field main store hoti hai energy

Watch video 2 of this playlist for detailed calculation of electric field in capacitor , you will get answer ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-tOGjhamuiPw.html

thanks sir in video 2 have two question 1. sheet is conducting or non conducting ?? 2. if it is conducting then when you calculate (E plus) then what about the factor of 2 because the electric field due to a conducting sheet is not sigma/2epsilon where am i wrong?

Parth Kasana good question, many students have this basic confusion. And to 1, it is a conducting plate without conducting plate you can't have capacitor. When I am calculating field due to just plus charge, it will be sigma / 2. Because the net field inside the conductor is zero but this field becomes zero when you include effect of both positive and negative plate charge. Till the time you are calculating field just due to plus charge, it will be equal in magnitude on both sides so by gauss law factor of 1/2 will come. When I have to find total electric field, field inside conductor is zero so now you apply gauss law, you will get sigma / epsilon without factor of 2 because E inside conductor is zero. What you are telling in point 2 that E for conductor will not have factor of 1/2 is true, but when you are calculating E just due to one plate the plus plate it will be half of total E so factor of 1/2 will come.

I think less

sure kam hoti ha

BE AND MAKE same question

in future paka..abhi thoda basic cover kar raha hoon

sir kya aap cbse class 12(physics) ke saare chapter cover kr skte hai?

pls watch video#18 on electric potential in this playlist

E=F/q. and V =w/q V=F.d/q

yes, but later -ve sign will be cancelled as final potential is zero > Vf-Vi=-Ed >--Vi=-Ed>Vi=Ed